# The ABC triangle is isosceles with the BC base. The straight line MK is parallel to the base M belongs to BC

**The ABC triangle is isosceles with the BC base. The straight line MK is parallel to the base M belongs to BC, K belongs to AB. Find the angles of the CME triangle if the angle B = 66 degrees, the angle C = 48 degrees.**

Given: isosceles triangle ABC:

base of the aircraft;

MK is parallel to the BC:

M belongs to the AC;

K belongs to AB;

angle B = 66 degrees;

angle C = 48 degrees.

Find the angles of the triangle KAM -?

Solution:

1) Consider an isosceles triangle ABC. Angle B = angle C = 66 degrees;

2) If MK is parallel to BC, then the angle KBC = AKM = 66 degrees, as these are the corresponding angles for these parallel sides and secant AB;

3) If MK is parallel to BC, then the angle BCM = KMA = 66 degrees as these are the corresponding angles for these parallel sides and secant AC;

4) Angle A is common. Then the angle KAM = 48 degrees.

Answer: 66 degrees; 66 degrees; 48 degrees.